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A 3300-V, 50-Hz, Y - connected, ten-pole induction machine has a magnetising resistance 250, magnetising reactance 40 per pha

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from given data, line voltage V =3300 V frequency f= 50 Hz no. of Poles P=10 star connected induction machine magnetising resstator current IF Noload t Secondary current coorent sef to primary II = Total Ig: Vph (RitgeJej(x+y) Uph = VL - 3300 =1905-Ils -148 Mognitude of I= 198.15 Amp phase angle of 054448 power factor = cos $ =COS(-148 20.84 dag Por mue qz vit ( 8 ) (Ceut6 from given data, herefore Torque is positive 2ile phases are reversed, then direction of speed reversed. ( slip is tue S-00111* 204.36€ 06-29-610° PF cos 6 =0.869° Torque Taver cck ( 83) 2TX NS [central)? (x1+421)2 60 = 190625 (0.4 oou 27*X120X50

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