Use bond energies to calculate ?Hrxn for the reaction.
2H2(g)+O2(g)?2H2O(g)
Note: The answer is NOT 442 kJ or 442kJ/mol
It gave me this hint when I got the answer wrong: The bond energies of H?H, O=O, and H?O are provided in the introduction. To determine the enthalpy of this reaction, sum all of the bond energies for the reactants (accounting for stoichiometric ratios as is), and subtract the bond energies for the product. Note how many bonds are in each molecule.
Use bond energies to calculate ?Hrxn for the reaction. 2H2(g)+O2(g)?2H2O(g) Note: The answer is NOT 442...
Hydrogen is burned according to the following chemical reaction: 2H2(g) + O2(g) → 2H2O(l) ∆Hrxn = -286 kJ Given 100 g of H2 and excess O2, how much heat is released?
Which statement describes how you can determine ∆Hrxn for the reaction of H2(g) and O2(g) to form liquid water, H2O(l)? Be sure to take into consideration the intermolecular attractions in H2O(l). 2H2(g) + O2(g) → 2H2O(l) A. You can only use bond energies. B. You can only use heats of formation. C. You can use either bond energies or heats of formation.
is this endo or exo? Use the following bond energies to decide if the reaction of CO2 +2H2 --> CH4 + O2 is endo or exo thermic. C--H 414 kJ/mol S C=O in CO2 = 799 kJ/mol 0=0 = 298 H-H = 436 Endothermic Exothermic
Calculate the standard entropy change for the reaction 2H2(g)+O2(g)?2H2O(l) using the data from the following table: Substance ?H?f (kJ/mol) ?G?f (kJ/mol) S? [J/(K?mol)] H2(g) 0.00 0.00 130.6 O2(g) 0.00 0.00 205.0 H2O(l) -285.8 -237.2 69.90 Express your answer to four significant figures and include the appropriate units. Please show me the steps on how to solve this!!! Thank you!!!
Given the following: O2 (g) + 2F2 (g)------> 2OF2 (g) delta H=+24.5 kJ/mol Bond dissociation energies: F2= 159 kJ/mol; O2 (double bond) = 498 kJ/mol Calculate the bond strength of the O-F bonds in OF2.
Calculate delta Hrxn for the following reaction: 5C(s)+6H2(g)--->C5H12(l) use the following reactions and given delta H's: C5H12(l)+8O2(g)---> 5CO2(g)+6H2O(g) delta H= -3505.8 kJ C(s)+O2(g)--->CO2(g) delta H= -393.5 kJ 2H2(g)+O2(g)---> 2H2O(g) delta H= -483.5 kJ The steps to solving this problem would be greatly appreciated! Thanks so much!
the enthalpy change in a chemical reaction can be determined using bond energies. energy must be added or absorbed to break bonds and that energy is released when bonds are formed. therefore ,you can calculate the total enthalpy of the reaction using following formula: dH= bonds broken-bonds formed Using bond energies, calculate the change in energy that accompanies the following reaction: H2 + O2 -> 2H2O Bond Bond Energy H-H 432 kJ/mol O-O 498 kJ/mol H-O 467 kJ/mol
Calculate the enthalpy for the reaction below using the following bond dissociation energies. • H-H 436 kJ/mol O-H 460 kJ/mol 0-0 180 kJ/mol • 0=0 498 kJ/mol H -774 kJ/mol -654 kJ/mol 654 kJ/mol 774 kJ/mol
Consider the reaction 2H2O(g) →2H2(g) + O2(g) ΔH = +483.60 kJ/mol at a certain temperature. If the increase in volume is 27.7 L against an external pressure of 1.00 atm, calculate ΔU for this reaction. (The conversion factor is 1 L· atm = 101.3 J.) _______kJ
Consider the reaction 2H2O(g) → 2H2(g) + O2(g) ΔH = +483.60 kJ/mol at a certain temperature. If the increase in volume is 42.7 L against an external pressure of 1.00 atm, calculate ΔU for this reaction. (The conversion factor is 1 L · atm = 101.3 J.) _______kJ