Question

Part B As shown, a triangle has a base of b-4.20 ft and a height of h = 5.10 ft . (Figure 1)What is kI' the triangle's radius of gyration about the x axis? Express your answer numerically to three significant figures and include the appropriate units. View Available Hint(s) kValue Units Submit

Answer 1

Part B Calculate the radius of gyration using the equation written below: R= o /12 V oh! 2 16 Solve for R. (5.10 ft) REV6 = 2.082 ft =2.1 ft. Part C Now, calculate the moment of inertia of the circle about the centre as follows: 1= Ar2 + Ad? Here, d is the distance between the points and in this case, d=r Therefore, the equation 1. == Ar + Ad is rewritten as follows: 1. = 4,2 + Ar? The expression for the polar radius of gyration is as follows: Rue v Solve for Robert

مانتا اتارا = (590A) = 7.22 ft Part D Also, the radius of gyration is, = ج 0 . 700 ft Again, the moment of inertial of the circle is as follows: And the area of circle is as follows: 1 = T-2 Also, لاني Solving further 0.700 ft:1 0 . 700 ج :n 0.700 ft: Now, solve for r as follows: 3= 0.700 ft 7 = 0.700 ft (2) = 1.4 ft.