Question

help me find the molarity of Sn2+

Redox Titration in Acidic Medium 504 Total 2. Push Slider Up to Add a Volume of K2Cr2O7 Volume of K2Cr2O7 Oxidizing Agent KMnO4 K2Cr2O7 Reducing Agent Fe2+ Sn2+ S2032- Reaction 1. Select the 40.52 ml 40.5 ml 3. After Titration, Calculate and Enter Molarity of Sn2+ Molarity of K2Cr2O7 51100 M M OK - Dropwise 3Sn2+ + Cr202-7+ 14H+ 3Sn4+ + 2 Cr3+ + 7H2O Repeat Volume of Sn2+ 25.00 ml Reset

Answer 1

Given equation - wwt 3 sn 3 Sht? + CD +1447 3 mole snt2 reacts with +268 + 7 tho cit] ? snt 4 ta 1 mole c802 Kcron/nor Snth M, = 0.511N ~ = 40.5 ml is added n = 1 M2 = 2 va = 25 MI ņ=3 - we know that Mill - Movie we know Mai Riven, substitute all the values nova Then (0.511M) (40.5 ml (3) (1) (25 mi) Qi48 19 concentration of sth = 2.48 M