What are the units of the rate constant for a reaction whose rate law is second...
What are the units of the rate constant for a reaction whose rate law is second order with respect to reactant A and zero order with respect to reactant B?
A. L * mol^-1 * s^-1
B. L * mol^-1 * s
C. L^2 * mol^-2 * s^-1
D. L^2 * mol^-2 * s^-2
E. L^-1/2 * mol^1/2 * s^-1
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What are the units of the rate constant for a reaction whose
rate law is second...
The rate law of a reaction is rate =k[X]³. The units of the rate constant are
1)The rate law of a reaction is rate =k[X]³. The units of the rate constant areL mol-1 s-1mol² L-2 s-1mol L-1S-2L² mol-2 s-1mol L-1S-12)Given the following rate law, how does the rate of reaction change if the concentration of Z is tripled? Rate =k[X]³[Y]²[Z]⁰The rate of reaction will increase by a factor of136803)What data should be plotted to show that experimental concentration data fits a first-order reaction?1 / [reactant] vs. time[reactant] vs. timeln (k) vs. Ealn (k) vs. 1 / Tln [...
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The rate law for a certain enzymatic reaction is zero order with respect to the substrate....
The rate law for a certain enzymatic reaction is zero order with respect to the substrate. The rate constant for this reaction is 4.6 times 10^2 M middot s^-1. If the initial concentration of the substrate is 0.338 mol L^-1, what is the initial rate of the reaction? rate = _______ times 10 _______ M middot s^-1
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The rate law for a general reaction involving reactant A is given by the equation rate...
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The second-order reaction, 2 Mn(CO)_5 rightarrow Mn_2 (CO)_10 is found to have a rate constant equal...
The second-order reaction, 2 Mn(CO)_5 rightarrow Mn_2 (CO)_10 is found to have a rate constant equal to 512 M^-1 S^-1. If the initial concentration of Mn(CO)_5 is 0.011 M, how long will it take for the reactant concentration to reach 0.0011 M? Units: s a. 1.6 b. 5.1 c. 0.020 d. 0.28 A plot of a 1/[A] versus time gave a straight line. This indicates that A rightarrow B + C a. the reaction is zero order in reagent A...
5. Given the reaction OCT (aq) + I (aq) → OT (aq) + Cl(aq) tienis Rate = k1110017. Th The rate law for this reaction is Rate =k! . The overall reaction order and the [OH"] order with respect to OH are A) 2 and -1. B) O and -1. C) 0 and 1. D) 2 and 1. E) 1 and -1. 6. The following data were obtained for the hypothetical reaction 2A + B → products, [A] (M) [B]...
The rate law for a certain enzymatic reaction is zero order with respect to the substrate. The rate constant for this reaction is 4.6 times 10^2 M middot s^-1. If the initial concentration of the substrate is 0.338 mol L^-1, what is the initial rate of the reaction? rate = _______ times 10 _______ M middot s^-1
Rate of reaction Rate law Rate constant Answer Bank always has units of amount per time (i.e., molarity per second, M/s, or molarity per minute, M/min) a formula that relates reactant concentration to reaction rate can have different units, such as molarity per second (M/s), inverse seconds (s), or inverse molarity-seconds (M-.-'), depending on the reaction order symbolized as k
The rate law for a general reaction involving reactant A is given by the equation rate = k[A]?, where rate is the rate of the reaction, k is the rate constant, [A] is the concentration of reactant A, and the exponent 2 is the order of reaction for reactant A. What is the rate constant, k, if the reaction rate at 450.°C is 1.23x10-1 mol/L.s when the concentration of A is 0.220 mol/L? 1/Mos When heated to 75°C, 1 mole...
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