Question

Rate of reaction Rate law Rate constant Answer Bank always has units of amount per time (i.e., molarity per second, M/s, or m

0 0
Add a comment Improve this question Transcribed image text
Answer #1


Rate of reaction Rate law Rate constant Answer Bank always has units of amount per time (i.e., molarity per second, M/s, or m

Add a comment
Know the answer?
Add Answer to:
Rate of reaction Rate law Rate constant Answer Bank always has units of amount per time...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Match the descriptions to the appropriate term. Rate of reaction Rate law Rate constant Answer Bank...

    Match the descriptions to the appropriate term. Rate of reaction Rate law Rate constant Answer Bank always has units of amount per time (i.e., molarity per second, M/s, or molarity per minute, M/min) symbolized as k can have different units, such as molarity per second (M/s), inverse seconds (s-1), or inverse molarity-seconds (M-1.s-1 depending on the reaction order a formula that relates reactant concentration to reaction rate

  • The rate law of a reaction is rate =k[X]³. The units of the rate constant are

    1)The rate law of a reaction is rate =k[X]³. The units of the rate constant areL mol-1 s-1mol² L-2 s-1mol L-1S-2L² mol-2 s-1mol L-1S-12)Given the following rate law, how does the rate of reaction change if the concentration of Z is tripled? Rate =k[X]³[Y]²[Z]⁰The rate of reaction will increase by a factor of136803)What data should be plotted to show that experimental concentration data fits a first-order reaction?1 / [reactant] vs. time[reactant] vs. timeln (k) vs. Ealn (k) vs. 1 / Tln [...

  • 1. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reacti...

    1. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reaction is run for 2.5 hours and the initial concentration of the reactant is 0.31 M? 2. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reaction is run for 2.5 hours and the initial concentration of the reactant is 0.31 M? 3. The rate constant...

  • The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...

    The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time...

  • Part 11: Integrated Rate Law 8 pts each If a second-order reaction with a rate constant...

    Part 11: Integrated Rate Law 8 pts each If a second-order reaction with a rate constant of 0.056 M's'has a reactant concentration of 1.2 M after 8.0 seconds have elapsed, what was the initial reactant c

  • The integrated rate law allow chemists to predict the reactant concentration after a certain amount of...

    The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...

  • Most of the time, the rate of a reaction depends on the concentration of the reactant....

    Most of the time, the rate of a reaction depends on the concentration of the reactant. In the case of second-order reactions, the rate is proportional to the square of the concentration of the reactant. Select the image to explore the simulation, which will help you to understand how second-order reactions are identified by the nature of their plots. You can also observe the rate law for different reactions. In the simulation, you can select one of the three different...

  • What are the units of the rate constant for a reaction whose rate law is second...

    What are the units of the rate constant for a reaction whose rate law is second order with respect to reactant A and zero order with respect to reactant B? A. L * mol^-1 * s^-1 B. L * mol^-1 * s C. L^2 * mol^-2 * s^-1 D. L^2 * mol^-2 * s^-2 E. L^-1/2 * mol^1/2 * s^-1

  • 1. Part: A The rate constant for a certain reaction is k = 6.00×10−3 s−1. If...

    1. Part: A The rate constant for a certain reaction is k = 6.00×10−3 s−1. If the initial reactant concentration was 0.550 M, what will the concentration be after 10.0 minutes? Part B: A zero-order reaction has a constant rate of 1.80×10−4M/s. If after 75.0 seconds the concentration has dropped to 7.50×10−2M, what was the initial concentration? 2. At 500 ∘C, cyclopropane (C3H6) rearranges to propane (CH3−CH=CH2). The reaction is first order, and the rate constant is 6.7×10−4s−1. If the...

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t 1/2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t 1/2 = 1 k[A ] 0 Part A A certain first-order reaction ( A→products ) has a rate constant of 9.90×10−3 s −1 at 45 ∘...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT