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Question 2 2 pts The mass of the tray in question 1 is 358 g. If the 1.035 N is force needed to pull the the tray at a steady

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& 2 mass of Tray (m) = 358g 20-358kg Constant velocity Tray > f Given tray is moving with Constant velocity Given Fr 1.035N.qN f frichon mg IN friction 1-035 zum ung u = 1035 00358x998 u = 0.2950062 u=0029519-3 mazs (m) – Thug = o-ripling Coefficient of Static friction 0659 u=ooo For the tray to Just start sliding The Force appli

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