Question

A load of bricks with mass m 14.6 kg hangs from one end of a rope that passes over a small, frictionless pulley. A counterweight of mass m2 J28.0 kg is suspended from the other end of the rope, as shown in the figure (Figure 1) T e system is released from rest. Use g 9.80 m/s for the magnitude of the acceleration due to gravity. Figure 1 of 1

A. What is the magnitude of the upward acceleration of the load of bricks?

B. What is the tension in the rope while the load is moving?

Answer 1

here

net force = (28 * g - 14.6 * g) = 13.4 * g

F = 13.4 * 9.8 = 131.32 N

acceleration = netforce / mass

a = 131.32 / (28 + 14.6) m/s^2 = 3.08 m/s^2

b)

Consider the load of bricks

force = mass * acceleration

T - 14.6 * g = 14.6 * 3.08

T = 188.048 N