2. A 40.0 kg wagon is towed up a hill inclined at 17.5° with respect to...

Question

Question

Answer 1

Answer #1

2.

a)

net acceleration

m a = T - mg sin x

40* a = 542 - 40* 9.8 sin 17.5

a = 10.6 m/s^2

using 3rd equation of motion

v^2 = 2 a d = 2 * 10.6* 73

v = 39.345 m/s

=======

b)

N = mg cos x = 240* 9.8 cos 17.5 = 373.86 N

====

plz post other problem separately

Comment before rate in case any doubt, will reply for sure.. goodluck

Answer 2

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