Question

1). A cart of mass M = 500 g on 20.0 degree incline plane is connected by a light string passing over massless pulley to the mass m=200 g hanging on the string. What is the acceleration of the cart (say, in +x downhill direction) acart = m/s', of the hanging mass amass m = m/s”, and how much is the tension in the thread T = 2) Two masses m=1.00 kg and M= 2.00 kg are hanging on a common thread passing over a pulley. How much is the acceleration of first mass ay = m/s? and the second mass a2 = m/s (say, as projected onto the vertical axis +y directed down). How much is the tension in the thread? T = -N 3) An elevator is moving up with constant speed v = 9.80 m/s. How much is the tension in the cable hanging the elevator if the mass of the elevator is 1000 kg? T= N. What if elevator is moving down with constant speed 20.0 m/s? T = 4) An elevator of the mass m=1000 kg is moving up with the acceleration a= 9.80 m/s. How much is the tension in the cable? T = N. What if the same elevator is moving down with the acceleration 4.90 m/s?? T = N. Is moving down with the acceleration a = 9.80 m/s' (is in free fall)? T=

Answer 1

Given Mea2 kg maz 1 kg meg a mi la mig mag From block at miaa mig- T i ) From block og сі) мат- та 9 Add rij and di (mit me) as g (min ma) g (mir mal - 98 (2-1) 2+ mitma la ? 3.207 mise and (T- 13.067 M 7

Given Mea2 kg maz 1 kg meg a mi la mig mag From block at miaa mig- T i ) From block og сі) мат- та 9 Add rij and di (mit me) as g (min ma) g (mir mal - 98 (2-1) 2+ mitma la ? 3.207 mise and (T- 13.067 M 7

ão as moving with constant seed - so we can werite Freet = W-T = 0 mg = T T= mg (1000) (9.8) = aroon when accelertion is zero, it does thin't matter elevator is moving up or down Enet zo so Tz 1980oN] Now elevator is moving up with ä 29.8 m 13² (1) mig We can write

mia- a T- mig miat mig micaag) = 1000 (9.849.8) IT- 19.68103N) It elevator is moving downward mg Freet = mas mg -T so T = mg-ma Ta mcg-aja TT= ON 1000 (9.8m 9.8)

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