According to the equation, 2 moles of NaHCO3 decomposes to form 1 mole of Na2CO3
Number of moles of NaHCO3 taken = mass/molar mass of NaHCO3 = 4.234/84.007 = 0.0504 moles
So, the number of moles of Na2CO3 should be produced = 0.0504/2 = 0.0252 moles
So, the theoretical yield of Na2CO3 = the number of moles * molar mass = 0.0252*105.988 = 2.671 g
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