Using Excel, go to Data, select Data Analysis, choose Anova: Two-Factor With Replication. No. of rows = 3
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Fertilizer | 3885.389 | 2 | 1942.694 | 10.928 | 0.000 | 3.403 |
Seed | 763.222 | 3 | 254.407 | 1.431 | 0.258 | 3.009 |
Interaction | 1377.278 | 6 | 229.546 | 1.291 | 0.299 | 2.508 |
Within | 4266.667 | 24 | 177.778 | |||
Total | 10292.556 | 35 |
H0: There is no difference in the effectiveness of the 3 fertilizers
H1: There is a difference in the effectiveness of at least two of the fertilizers
p-value = 0.000
Since p-value is less than 0.05, we reject the null hypothesis.
There is a difference in the effectiveness of at least two of the fertilizers. (B)
H0: There is no difference in the growth of the four types of seeds
H1: There is a difference in the growth of at least two of the seeds
p-value = 0.258
Since p-value is more than 0.05, we do not reject the null hypothesis.
There is no difference in the growth of the four types of seeds. (C)
Answer: Both B and C (Option D)
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