∆Tb = 1000×Kb×w/W×m
W is mass of solvent, w is mass of solute ,m is molecular mass of solute.
∆Tb =(Tf-100) =1000×0.512×1/4.450×62
Tf-100 = 1.98
Tf = 100+1.98 =101.98℃
A 1.00 kg sample of ethylene glycol (C_2 H_6 O_2) is added to 4450 g of...
8. Ethylene glycol, HO-CH2-CH2-OH, a nonelectrolyte, is added to the water in a radiator to give a solution containing 515 g of ethylene glycol in 565 g of water. a. What is the molality of this solution? b. What is the boiling point of this solution? (Kb = 0.512 °C kg/mol for water)
How many liters of the antifreeze ethylene glycol [CH_2(OH)CH_2(OH)] would you add to a car radiator containing 6.50 L of water if the coldest winter temperature in your area is -13 degree C? (The density of ethylene glycol is 1.11 g/mL. Assume the density of water at -13 degree C is 1.00 g/mL.) L Calculate the boiling point of this water-ethylene glycol mixture. degree C
What is the boiling point of a mixture composed of 90.0 g HOCH2CH2OH (ethylene glycol, MM= 62.068 g/mol) and 120.0 g H2O? The boiling point elevation constant for H2O is 0.512 °C/m. Boiling point of a pure water under the same condition is 100.0°C.
[References] What volume of ethylene glycol (C2HO2), a nonelectrolyte, must be added to 12.0 L water to produce an antifreeze solution with a freezing point of-19.0°C? (The density of ethylene glycol is 1.11 g/cm°, and the density of water is 1.00 g/cm³. K, for water is 0.51°C•kg/mol and Kf is 1.86°C kg/mol.) Volume %3D What is the boiling point of this solution? Boiling point °C %3D 5 item attempts remaining Submit Answer Try Another Version [References] Consider an aqueous solution...
An ethylene glycol solution contains 27.6 g of ethylene glycol (C2H6O2) in 92.0 mL of water. (Assume a density of 1.00 g/mL for water.) Determine the freezing point of the solution. Determine the boiling point of the solution.
An ethylene glycol contains 22.2 g of ethylene glycol (C_2H_6O_2) in 82.4 mL of water Calculate the freezing point of the solution. (Assume a density of 1.00 g/mL for water.) Calculate the boiling point of the solution.
An ethylene glycol solution contains 24.4 g of ethylene glycol (C2H6O2) in 85.4 mL of water. (Assume a density of 1.00 g/mL for water.) 1.Determine the freezing point of the solution. 2.Determine the boiling point of the solution.
what mass of ethylene glycol must be added to 1455 g of water to raise to boiling point to 104.7 degree Celsius. _____ g ?
6.25 A 27.7 g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initiai temperature of the ethylene glycol if the final temperature is 32.5 e? (s of ethylene glycol 2.42 J/g. c) 627 One piece of copper jewelry at 105 C has exactly twice the mass of another piece, which is 45 °C. Both pieces are placed inside a calorimeter whose heat capacity is negligible. What is the final temperature inside the...
How many liters of the antifreeze ethylene glycol [CH2(OH)CH2(OH)] would you add to a car radiator containing 5.50 L of water if the coldest winter temperature in your area is −20.0°C? Calculate the boiling point of this water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL.) What is the volume of antifreeze? L What is the boiling point of the solution?