Question

Problem-3 A very small but very heavy ball is thrown directly upward from the ground level with a speed of 12.5m/s. (a) What is the maximum height above the ground reached by the ball? (b) What is the total time after being thrown from the ground that it takes for the ball to reach the ground again? (c) What is the velocity of the ball when it hits the ground?

Answer 1

a) We know. kottaa v=untzan 1 Here if the ball is thrown vertically upwart, then u- 12.5 m/s aang so we ungs If s hmans (m animum height), then u-o (at highest point, there is no velocily) so max = 12.5 m (8-9.8 m/s) -7.97 m - . When the ball will add fall to the ground, vertical distance travelled will be taro. If time of flight is 8 T, then from wurzes s= ut + hata we can white, = UT - 1972 - T- 26 - 2.55 ss c) we know, kaut at Euras. At height point delocity is rero If we consider only downward motion then uso aag so, 5=2gs - 2x9.8 xhman ground 12.50 m/s As it should be, since there is no air resistanco so energy must remain conserved.