B)
CO + NH3 = HCONH2
K = 0.77
CO = 1
NH3 = 2
HCONH2 = 0
in equilibrium
CO = 1 - x
NH3 = 2 - x
HCONH2 = 0 + x
then
K = HCONH2 /CO*NH3
0.77 = (x)/(2-x)(1-x)
1.29870129x = 2-3x+x^2
x^2 - (1.29870129 +3)x +2 = 0
x = 0.53
since
HCONH2 = 0 + x = 0.53M
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