Ans 2
The dissociation reaction
Ag2CrO4 = 2Ag+ + CrO4(-2)
Ksp = [Ag+]^2 [CrO42-]
let x = mol/L
Molarity of Ag2CrO4 = x
Molarity of Ag+ = 2x
Molarity of CrO42- = x
2 * 10^-12 = (2x)^2 * x
4x^3 = 2*10^-12
x = 8.722 * 10^-5 = molar solubility of Ag2CrO4
2. Calculate the molar solubility of Ag:CrOs at 25 °C given that the Kip for the...
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