Question

Find the tension in cable ?? using the values for ?1, ?2, ?, ? and ???? given in the table. The tension in cable ?? is known to be approximately 97.2236 N.

Find the tension in cable AC using the values for L1, L2, a, ß and Mass given in the table. The tension in cable BC is known to be approximately 97.2236 N. L1 L2 400 mm 525 mm 25° 41° 10 kg 9.8 m/s2 Mass 9

Answer 1

Pago ON Resolving the forces TI Cosa sx T2 cos

Here,

Let tension on AC = T1

Tension on BC = T2

We will resolve the tension force into its horizontal and vertical component.

Vertical Component for cable AC

T1sina

= T1sin25

Vertical component of cable BC

=T2sinB

=T2sin41

Also horizontal component for Cable AC

=T1cosa

=T1cos25

Horizontal component of cable BC

=T2cos41

Now if resolve the forces horizontally , we see only two force act and in opposite directions

T1cos25 - T2cos41 =0

T1cos25 =T2cos41

0.90631T1=0.75471 x T2

T1=(0.75471 T2)/0.90631

T1= 0.83273T2

Now forces acting on vertical direction

mg -T1sin25 -T2sin41 = 0

10 x 9.8 - 0.42262T1 -0.65606T2 =0

98 - ( 0.42262 x 0.83273T2) - 0.65606T2 =0

98 - 0.35192T2 -0.65606T2 = 0

1.00798T2 = 98

T2 = 98/1.00798

T2 ≈ 97.2234N ANSWER