![4. 12 pt] Combine all the R, L, C component into a single impedance (i.e. equivalent impedance), then apply Ohms law in Phasor domain to calculate the current. Express your answer in the time domain i(t). itt)-? 820 100pF 50Hz 33mH 100mH 100?](http://img.homeworklib.com/questions/e55d07b0-4597-11eb-8cee-bbc7977ca41b.png?x-oss-process=image/resize,w_560)
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4. 12 pt] Combine all the R, L, C component into a single impedance (i.e. equivalent...
The single-phase circuit shown in Figure. 1 is operating at steady-state. R;=1000 G=10F L=0.05 H C...
The single-phase circuit shown in Figure. 1 is operating at steady-state. R;=1000 G=10F L=0.05 H C = 2001F1 ZL.+0.2H R=2002} @va Vs1 V2*10000/10000) M Vs2 V2200Cos(1000+30) M Figure. 1: Single-Phase Circuit 1. Represent the circuit in the phasor domain. Show the impedance value for each passive component of the circuit and the phasor value for each voltage source. 2. Using the circuit in phasor domain calculate the value of each branch current and the complex, apparent, active, and reactive powers...
1. Why can the DSO only measure node voltages when the Function Generator is the power supply in ...
1. Why can the DSO only measure node voltages when the Function Generator is the power supply in a circuit (unless it is using a current probe)? 2. Consider Figure 1. According to the calculations in the lab handout, if Z-1kΩ +/6914, then the phase difference (фи-фі) between u(t) and i (t) is 34.6". a. If this v(t) and i(t) were displayed on a DSO (v(t) being a node voltage and using a current probe for i(t) as shown in...
1. RL Circuits For the circuit in Figure 1, find the inductor voltage vit) if a)...
1. RL Circuits For the circuit in Figure 1, find the inductor voltage vit) if a) v(t) is the step function: 0 Vfor t<0 and 10 V for t>0. What is the time constant in this case? b) vs(t) 15 cos(100 t). You may use either the direct time-domain method, or use (complex) phasor method. 52 102 5mH L(t) Figure 1 2. Impedance You are given six black boxes, labelled "1" to ", each with two terminals. You are told...
es anh th e c dfe sod aao rt34e k-e: e fi、c ︵ee aod g ti r mdfdpe hrr nd s pt Ide r. csa reu etnn doi ers inas dav si a)rec.z trlar k-te eer 0 dkne nro li ob "bee tdgu sa 9 edeb onfr fr cfr pge...
es anh th e c dfe sod aao rt34e k-e: e fi、c ︵ee aod g ti r mdfdpe hrr nd s pt Ide r. csa reu etnn doi ers inas dav si a)rec.z trlar k-te eer 0 dkne nro li ob "bee tdgu sa 9 edeb onfr fr cfr pgeo etg 0 uet tio edl tnd gra .1.1 euds P Hall in re ce capacitor C1 omitted. Therefore, VFB(t) VouT)/32. We assume g -800 What is the actual gain of...
The single-phase circuit shown in Figure. 1 is operating at steady-state. R;=1000 G=10F L=0.05 H C = 2001F1 ZL.+0.2H R=2002} @va Vs1 V2*10000/10000) M Vs2 V2200Cos(1000+30) M Figure. 1: Single-Phase Circuit 1. Represent the circuit in the phasor domain. Show the impedance value for each passive component of the circuit and the phasor value for each voltage source. 2. Using the circuit in phasor domain calculate the value of each branch current and the complex, apparent, active, and reactive powers...
1. Why can the DSO only measure node voltages when the Function Generator is the power supply in a circuit (unless it is using a current probe)? 2. Consider Figure 1. According to the calculations in the lab handout, if Z-1kΩ +/6914, then the phase difference (фи-фі) between u(t) and i (t) is 34.6". a. If this v(t) and i(t) were displayed on a DSO (v(t) being a node voltage and using a current probe for i(t) as shown in...
1. RL Circuits For the circuit in Figure 1, find the inductor voltage vit) if a) v(t) is the step function: 0 Vfor t<0 and 10 V for t>0. What is the time constant in this case? b) vs(t) 15 cos(100 t). You may use either the direct time-domain method, or use (complex) phasor method. 52 102 5mH L(t) Figure 1 2. Impedance You are given six black boxes, labelled "1" to ", each with two terminals. You are told...
es anh th e c dfe sod aao rt34e k-e: e fi、c ︵ee aod g ti r mdfdpe hrr nd s pt Ide r. csa reu etnn doi ers inas dav si a)rec.z trlar k-te eer 0 dkne nro li ob "bee tdgu sa 9 edeb onfr fr cfr pgeo etg 0 uet tio edl tnd gra .1.1 euds P Hall in re ce capacitor C1 omitted. Therefore, VFB(t) VouT)/32. We assume g -800 What is the actual gain of...
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