Calculate the amount of heat (in kJ) required to raise the temperature of 14.0 g of...

Question

Question

Answer 1

Answer #1

Amount of heat required to raise the temperature from 25°C to 100°C (boiling point of water):

q1 = mc delta t

Given:

m = 14g

c = 4.18J/gC

delta t = (100-25)C = 75°C

q1 = 14×4.18×75 = 4389J = 4.389kJ

Latent heat needed to change liquid water to vapour

q2 = mL

L = heat of vapourization = 40.7kJ/mol

Moles of water = 14g/18g/mol = 0.77mol

q2 = 0.77mol × 40.7kJ/mol = 31.65kJ

Total heat = q1 + q2 = 4.389 + 31.65 = 35.85kJ

Heat required = 35.85kJ

Answer 2

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