Question

Sy guy I had No idea what subject to put this , so I put under advance physics

7) A neutron collides into a uranium-235 nucleus & split to one barium-139 nucleus and one Krypton-95 nucleus while emitting one additional neutron. In this fission reaction, a lot of energy is released. Calculate roughly what is the mass average daily electricity consumption of a HBD household in 2015.

Data:- Mass of uranium-235 nucleus =235.044 amu

Mass of barium-139 nucleus =138.909 amu

Mass of krypton-95 nucleus =94.940 amu

Mass of neutron =1.009 amu

Speed of light =3.00 x 108 m/s

1 atomic mass unit (amu) =1.66x 10-27 kg

1 kilowatt-hour(kWh) =3.60x 106 J

8) As we consider each renewable energy source, think about the relevant technologies involved in the harnessing and transmission of energy and the effects on society and the natural environment.Give 2 example and find relevant to support your answer.

9) Find out the efficiency of wind and water power compared to fossil fuels.Can you build a strong case for adopting these two renewable sources?

10) Find out the production capacity of the largest solar power plant available and the land area required, and the consumption of electricity for a developed country(eg. Singapore & The United State) for a year. What would the total area of all the solar panel be?

11) Why is a particulate matter pollution particularly high in developing countries? Consider the sociological factors that might aggravate such a situation.(You may also want to consider specific countries as cases)What is the reason for the correlation?

12) In the case of Singapore, How do the factors of food access, food use, and food stability determine its food security? Pls provident relevant to support your answer.

Answer 1

Average electricity consumption by HDBD household is = E_A upsilon energy released in one^235 bigcup decay is Rightarrow^235 bigcup + n rightarrow^139 Br +^95 kr + n Q = m (^235 bigcup + n) - m (br + kr + n) Q = [235.044 + 1.009 - (138.909 + 94.940 + 1.00 +) amu times 931.5 m e v/amu Q = 1113.1425 m e v no of atom (^235 bigcup) used in daily use of HBD consumption = E/1113.1425 times m e v N_1 = E_Av (j) times 5.607 times 10^15 mass of bigcup = N_1 times 235 times m_p \r\n mass of bigcup = N_1 times 235 times m_p mass = E_Av (j) times 5.607 times 10^15 times 235 times 1.67 times 10^- 27 mass = E_Av (j) times 2 times 10^- 9 kg/day uparrow energy in jule