Question

-1 ft-o-1-1 8. The 7 ft tall cabinet shown at right has a weight of 160 lb and a center of gravity that is 3.5 ft from the floor as shown. A horizontal force Pis applied to the side at a height of 4.0 ft from the floor. The coefficient of static friction between the legs and the floor is us= 0.2 and the coefficient of kinetic friction is fix=0.15. f. 19 points) If the applied force is 35 lb, will the cabinet slide without tipping or tip while sliding? To start, you can assume that the cabinet is accelerating. g. [3 points) What is the acceleration of the cabinet when this force is applied? If the cabinet is tipping, also compute the initial angular acceleration. h. [2 points] Validate the initial assumption that the cabinet is accelerating 41 3.5 ft

Answer 1

Given:- The system shown in figuer weight of cabinet w=1balb length of cabiner = 7 ft (3.5ft 46+ G fw Tff Tfil 3.5ft hight of force applied, h= 4 ft static friction coefficient, ey= 0.2 kinenic friction, MK = 0.15 MEN N of force applied p= 35 lb normal reaction, N W = 160db friction force, M = 160x 2 = 32 ebap hence cabinet are slipping sliding moment about point B - mg = Px4 - Wy! = 3544 - 160x1 140-160 = -20 MBLO Hence cabiner one sliding without tipping. ܟܘ acceleration of cabinet, P-UKU q= g= 41.9843) 35-0.15x160 ( 16961 2.88 f4f5? CI Initial assumption that the cabiner is arrelerann a crelerating- moment are to force applied pa moment clue to Scanned with Cams Conight of cabiner abour point B. CS