1) Solubility of CO2 in water = 0.15 g/100 ml
Moles of CO2 = Mass/molar mass = 0.15/44 = 0.00341 moles
Volume = 100 ml = 0.1 liter
Solubility of CO2 in Mol/Lit = S = 0.00341/0.1 = 0.0341 M
We know that;
S = K * P
S is molar solubility , K is Henry constant for CO2 and P is pressure.
P = 760 mmHg = 1 atm
0.0341 = K * 1
K = 0.0341 M/atm
Again apllying same equation;
S' = K * P
S' = 0.0341 * 4.1 = 0.1398 M = 0.14 Mol/Liter ....Answer
2)
24% (w/v) means 100 ml solution contains 24 g of glucose.
100 ml solution contains 24 g glucose
So, 305 ml solution will contain = 24 * 305/100 = 73.2 grams
So, mass of glucose = 73.2 g OR 73 g (approx) ....Answer
Let me know if any doubt.
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