Solution:
Given that
Here, it has the laurent series representation about point i.e,
Now,
The series
Hence,
we proved that
(valid for )
= t a r has a Laurent series representation about the 2. Show that f(s) =...
(b) Determine the largest R such that the Laurent series of 2+1 f(z) = z 1 + (z-iT)(z+T) converges for 0< z-1|<R (b) Determine the largest R such that the Laurent series of 2+1 f(z) = z 1 + (z-iT)(z+T) converges for 0
evaluate the following integrals. please show procedure. Develop g(z)= 1/(z-1)(z-2) into a laurent series that is valid for the following anular domains. 4) 23. 01/22 dz Y a) r=1121=5), bydle-il-24 Sol: Ti r = {12-21 = 2 3 4 Sol: Ti 1 5) S dz 23(2-1) 4 r 6) J ze² z ²-1 dz 8=2 Izl=2) Sol: 2li cash (1) Y 9) 0시레시 (o) 0 12-2[J.
Q3: 5 marks (A) Expand f(z) (2-1)(2-3) in a Laurent series valid for (i) Iz - 11 < 2, and (ii) Iz - 31 < 2. 1.5 marks each part (B) Use Laurent series to find the residue of f(2)= e (x - 2)-2 at its pole z = 2. 2 marks
A) B) C) 1 Find the Laurent series for 22 +22 for 0 < 121 < 2 Find the Laurent series for (z+2)}(3-2) for 2 – 3) > 5 1 Find the Laurent series for z2(z-i) for 1 < 12 – 11 < V2
question 5c 5. Find the Laurent series expansion of: (a) f(x) = 2*1 about i, (b) f(x) = 22 + 1-2, convergent on {2 < 121 <4}, (c)* f(x) = 2,2-33+2, convergent on {j < lz - 11 < 1}.
2. Find three different Laurent series representations (about 0) for the function 3 f(z) 2. Find three different Laurent series representations (about 0) for the function 3 f(z)
1 9. Expand f(z) = (2-1)-(2-6) as a Laurent series a) for 12-11 > R. R=? (Note: Pay attention, it is for >R, NOT <R.) b) for 12 - 41 <K. K=?
(C)!!!!! 5. Find the Laurent series expansion of: 1 (a) f(x) = 1 about i, (b) f(x) = 22 + atz, convergent on {2< 121 < 4}, (c)* f(x) = 273-33+2, convergent on {{ < \z – 11 <1}.
complex anaylsis f(2)= 22 2z 2²+1 For each annulus region below, find the Laurent series of fiz) convergent convergent in the region (i) OC/Z-il<2 12IZI
Do Task 212 Task 211 (C). Find the Laurent series of exp z exp-, and exp-2 at zo = 0. From the definition of the coefficients for the Laurent series off at zo, we see that a-1 = Res(f, zo). Sometimes it is easier to find the Laurent series than the residue directly Task 212 (C). Using the results of Task 211, find Res (exp 1,0), Res(-exp z,0), and Res(exp "In fact, given a function f(z) that is holomorphic on...