Question

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Suppose a sample of 707 floppy disks is drawn. Of these disks, 630 were not defective. Using the data, estimate the proportion of disks which are defective. Find your answer as a decimal number rounded to three decimal places. Using the data, construct the 95% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places. O proportion of disks which are defective is 0.109, confidence interval (0.786,0.892) O proportion of disks which are defective is 0.109, confidence interval (0.086,0.132) O proportion of disks which are defective is 0.901, confidence interval (0.187,0.232) O proportion of disks which are defective is 109%, confidence interval (8.9%,15.2%)

Answer 1

NITOF, X = 707-63.0 - 77 Þ = * = 77 = 0.109 707 le = 95% = 0.95 = 0/16/8 2 = 1 095 = 0-055 2/2 = 0-025 Za/2=Z0-025 .: =1-96 95% confidence Interval 0.109 & 1.96 * 10.100 707 1.96*0.01172 = 0.109 & = 0'109 + Ans 0 » 02297 = 10.086 ,0.132 proportion & of disks which are defective is 0.109, confidence interval (0-086, 0-132 )