A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 1 of 2: Suppose a sample of 985 floppy disks is drawn. Of these disks, 917 were not defective. Using the data, estimate the proportion of disks which are defective. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Suppose a sample of 985 floppy disks is drawn. Of these disks, 917 were not defective. Using the data, construct the 85% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.
Proportion of disks which are defective = Number of disks which are defective / Total number of disks
Total number of disks = 985
Number of disks which are defective = 985 - 917 = 68
Proportion of disks which are defective = p = 68 / 985 = 0.069
Now, we find the confidence interval for the population proportion of disks which are defective using the formula :
We have p = 0.069
n = 985
Using Standard Normal Tables we get :
Putting all the values in the above expression we get ,
So, 85% confidence interval for the population proportion of disks which are defective is : ( 0.057 , 0.081 )
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