Question

Problem 4. (25pts.) Three lon 12-I-21. They are reference distance a- 2cm Find, at the point P on the triangle, g parallel wires carry the following currents: 11-SA placed and directed as shown in the figure below where the a) (Spts.) The )5pts.) The magnitude and direction of the magnetic field caused by current 1 magnitude and direction of the magnetic field and caused by current Ii p The magnitude and direction of the magnetic field caused by eurrent b e) (Spts.) Sketch the magnetic felds in questions a through e I3 12 ai

Answer 1

Magnitude of magnetic field at a distance
Magnitude of magnetic field at a distance�r�due to a straight current carrying wire is�B = mu_0 I/2 pi r a)Magnetic field at point P due to�l_1 is B_1^vector = mu_0 I_1/2 pi(squareroot 2a)(1/ squareroot 2 i^^- 1/ squareroot 2 j^^) = (4 pi * 10^- 7) * (5)/2 pi * (squareroot 2 * 0.02)(1/ squareroot i^^- 1/ squareroot 2 j^^) B_1^vector = 2.5 * 10^- 5(i^^- j^^)T Magnitude of magnetic field at P due to I_1 is B_1 = 3.54 * 10^- 5 T, and directions theta = - 45 degree (that is 45 degree below the X - axis) b)Magnitude field at point P due to I_2 is B_2^vector = mu_0 I_2/2 pi (a) (- j^^) = (4 pi * 10^- 7) * (2 * 5)/2 pi * (0.02)(- j^^) = 1 * 10^- 4(- j^^)T Magnitude of magnetic field at P due to I_2 is 1 * 10^- 4 T and direction is
due to a straight current carrying wire is

a)Magnetic field at point P due to $I_1$ is

Magnitude of magnetic field at P due to $I_1$ is , and direction is   ( that is below the X-axis)

b)Magnetic field at point P due to $I_2$ is

Magnitude of magnetic field at P due to $I_2$ is and direction is towards Negative Y-axis.

c)

Magnetic field at point P due to $I_3$ is

Magnitude of magnetic field at P due to $I_3$ is and direction is towards Positive Y-axis.

d) Total magnetic field is

e)