ZuoTi.Pro
Question

the operation manager at the tire manufacturing company believes that the mean mileage of a tire...

the operation manager at the tire manufacturing company believes that the mean mileage of a tire is 47,225 miles, with a standard deviation of 3178. what is the probability that the sample mean would be less than 47,050 miles in a sample of 208 tires if the manager is correct? ( round your answer 4 decimal places and show work)

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Given . an ( 1人) 二 ー3148

0 0
Add a comment
Know the answer?
Add Answer to:
the operation manager at the tire manufacturing company believes that the mean mileage of a tire...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The operation manager at a tire manufacturing company believes that the mean mileage of a tire...

    The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 37,014 miles, with a standard deviation of of4617 miles. What is the probability that the sample mean would be less than 36,435 miles in a sample of 56 tires if the manager is correct? Round your answer to four decimal places.

  • The operation manager at a tire manufacturing company believes that the mean mileage of a tire...

    The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 49,36049,360 miles, with a variance of 6,568,9696,568,969. What is the probability that the sample mean would differ from the population mean by less than 231231 miles in a sample of 247247 tires if the manager is correct? Round your answer to four decimal places. CAN YOU PLEASE SHOW ME HOW TO DO THIS IN CALCULATOR TI-83 PLUS SPECFICALLY

  • The operation manager at a tire manufacturing company believes that tge mean mileage of a tire...

    The operation manager at a tire manufacturing company believes that tge mean mileage of a tire is 44,111 miles, with a variance of 5,943,844. What is the probability that tge sample mean would be greater than 44,257 miles in a sample of 80 tires if the manager is correct?

  • The quality control manager at a computer manufacturing company believes that the mean life of a...

    The quality control manager at a computer manufacturing company believes that the mean life of a computer is 120 months, with a standard deviation of 10 months. If he is correct, what is the probability that the mean of a sample of 90 computers would be less than 117.13 months? Round your answer to four decimal places.

  • The quality control manager at a computer manufacturing company believes that the mean life of a...

    The quality control manager at a computer manufacturing company believes that the mean life of a computer is 83 months, with a standard deviation of 99 months. If he is correct, what is the probability that the mean of a sample of 78 computers would be less than 82.06 months? Round your answer to four decimal places.

  • The quality control manager at a computer manufacturing company believes that the mean life of a...

    The quality control manager at a computer manufacturing company believes that the mean life of a computer is 117 months with a standard deviation of eight months if he is correct what is the probability that the mean of a sample of 52 computers would be less than 115. 46 months round your answer to four decimal places

  • The mileage that car owners get with a certain kind of radial tire is normally distributed...

    The mileage that car owners get with a certain kind of radial tire is normally distributed with a mean of 70,000 miles. If 97.725% of these tires lasted less than 78,000 miles, please calculate the standard deviation for the tire mileage. [Note: Please round your result for the standard deviation to the nearest integer.]                                                               [2 points] What is the probability a randomly selected tire of this type will last 65,000 miles? Please justify your answer.                                                                        [1 point] Calculate the probability...

  • The quality control manager at a computer manufacturing company believes that the mean life of a...

    The quality control manager at a computer manufacturing company believes that the mean life of a computer is 105 months, with a variance of 81 If he is correct, what is the probability that the mean of a sample of 70 computers would differ from the population mean by less than 1.9 months? Round your answer to four decimal places.

  • 1. Suppose that a tire manufacturer believes that the lifetimes of its tires follow a normal...

    1. Suppose that a tire manufacturer believes that the lifetimes of its tires follow a normal distribution with mean 50,000 miles and standard deviation 5,000 miles. a) Determine the probability that a randomly selected tire lasts for more than 57,500 miles. Also express this probability in terms of the function phi, the cdf of a standard normal distribution. b) Determine the mileage such that only 25% of all tires last for longer than the mileage you are determining. Also report...

  • A tire manufacturer believes that the tread life of its snow tires can be described by...

    A tire manufacturer believes that the tread life of its snow tires can be described by a normal model with a mean of 32,000 miles and a standard deviation of 2500 miles. Now, assume we took a sample of 26 tires. Find the probability that the tires will last an average of more than 33,500 miles. Round to three decimals.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT