The operation manager at a tire manufacturing company believes that the mean mileage of a tire...
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 49,36049,360 miles, with a variance of 6,568,9696,568,969.
What is the probability that the sample mean would differ from the population mean by less than 231231 miles in a sample of 247247 tires if the manager is correct? Round your answer to four decimal places.
CAN YOU PLEASE SHOW ME HOW TO DO THIS IN CALCULATOR TI-83 PLUS SPECFICALLY
Homework Answers
SD = sqrt(6568969/247) = 163.0798
Lower = 49360-231 = 49129
Upper = 49360+231 = 49591
2ND+VARS --> normalcdf
Ans : 0.8434
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The operation manager at a tire manufacturing company believes
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