Question

8 A proton accelerates from rest in a uniform electric field of 340 N/C. At one later moment, its speed is 1.2 mm/s. Over what time interval does the proton reach this speed? * (3 Points) 3.7 x 10-55 3.9 x 10-5 s 3.5 x 10-55 2.0 x 10-55 3.3 x 10-5 s

Answer 1

F GE for infinite sheet ss an de facely suspended body of weight log against gainitational bus : Since force sfb 38 - Pre- fs= -mg atla 116710 39.8 2 361TX10S 40-7x10-6 16x103 - 9,8x2 367x0.74103 527096 3.96*10 cm?

8) Fe = QE Fe IF = ma ma Fe q E = ma que (1.631014) (340), a 1.67x10-27 a= 3.257 X10'0m/s2 Vi= 0 m/s vf = 1.2x106 mis a = bep? 3.257x10"m/s2 Vf - Vitat 1:2X1065 3.257x1dct) ta 1-2 +10-4 3.257 c 3, 7x10 sec

10) 4.) 1 +xaus 61,0) qir 4MER? quc que 0 two Here there are thote charges Consider Er due to point charge auc al *-. .6 axlo + + 4y 4110 [110:4)] -2x106 E2 = 40E [4 1.42] htluý 1-42 6. -0.78 10 &x106 از بهر - و انها ۰ & exto,+E STX 109 4ITE ( 141-42)/1714 axax106 411 (6.092) 31x109 Eity = 4x3671x 10 An (5.092) 36x1031 5.092 ET 7069.13 NIC 3 A 1 c 7 9 = loom »r=10cm. a = 32uc. uniform charged sphere Apply Gaurs kw. IS E DA & Qenc E E Lda: Qenc Ilda = surface area of Sphere having Raticm. 52x103367X103 4 11 x04x102)2 -6 32x10. En 36104109 X411R² 14-7X10CNC