Question

Please use miller approximation assume no transistor parasitics and only the capacitor given in the sigure ,

NMOS :

gmn = 1ms

ron = 100k ohm

_____________

PMOS :

gmp = 500ns

rop = 100k ohm

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a)

1- what is the domain pole frequency of the amplifier.

2 - calculate all poles of this amplifier

b) is there a zero frequency associated with this amplifier? If there is what is the zero

b) Is there azero fretuency associate with this amplifier? if there is, what is the zoo sret? T - Voor ePF 2PF 9 lok steun pleas use Miller approximation. Assume no transistor Parasitics and only the capacitats given in the figure, NMOS Phos 9mn=lms Imp= 5ooks Ton=lookin rops looker Express your answers in HZ e), what is the dominant fole frequency of the amp? calculate all the foles of this еме!:4»er. Big 2omir

Answer 1

gevad va _dm Av= -Joy (Ropillon) En1 (510) Voz-a [m3 1 Rop SPF Voor meeropp JAV = -3.33]WW. lok • Miller apporximation . 2 pF Vinot to Vocet eftir This is Cascode menth Amplifier with Cascode Current Source Vout = Vins Av - . ' Vout ini? Vin op 7 oprla nos f **(4 %) a= 2pf(1+3.33) Tai = 8.66PF] Ropa (guroa) rof = gmprop? :- Roma (gmě roz) to, gun son - gno = gma = gmin Imalan gmg=gma - Jmin = 500 Malu = 0.5 mal In hand written question :: Igman 1 Co = 2F ( 143523 ) = 2:6 PF Now, redraw the fight pued , F 005 soo Ms nor ns T T Ti + 2.6ff 2017 : Intrinsic gain of cascoder Amplifier Ava-gmo Roplifpon) L244 Ico dok Rop = gmp top = 0.5*Coo - 6.5 to up, a vodnie z 41055*to nadlec 2 Ropa 5 kez = 1.84 MHz Ron= gm, row)² = 11 (100) = loka (Repllon) *(1072-6)tote 50 012-6+109 = 23.81 410G sad/sec Ifpz = 3.79 MHz •wpqor fp is dominant Pole.

L ① Yes there is zero in the Amplifier t han a Thumb rule to find zero w to seen, Number of path from Inpect to output Due to presence of 2PF of Capacitance, there is alter- native path Exist apart from regular ones this أعوق 6 .أيا مرع Vout hot (Ron Rop) Rout' OPE ct . i Vest - gaff Resort Route Yout= -gm, & Rout. /allite) 7 shoutte Vout IR - Itsa Rout SCOTSC) J + s Rource] above equation is derived wring sceperposition. MARET

s Route Vout = r Rout - gil Ll+secta) Rout] (Lt. Sc Rout t-s Routte) : gmi Pout [148 CzReut +Be+Rinut ] + s Rout ce [1+ 8 (60+C1) Race] (its (etc.) Rout) (itse peut + Ratce) -Jm Rout [ltsCutée) Rour] + s Cc Rout (scaten) Ronet] CH8(eta) Rour) ? = Equating Numerator to zero . Guapolet' [lt scette Trat] = ssc Right [lt Blete) Raca'] gmn 1x 10-3 1x10 NX Zero W2= ncc 29*2#loh [f2 = 79.58 MHz to here is app capacitance tựans Conductance of mind ami