Question

Take the derivative of each of the following 3t = 1. g(x) = (3x2 – 22 )4 2. r(t) t2+1 3. f(z) = (5x+1)3 sin^2 4. f(x) = cos (
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Answer #1

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Here is the attached Image of explanation of each question.

Solution for Question 1

4 Given g(x) = (3x2 – 2x) let y = 3x2 2x g(x) =yt Now; gf(x) = 44() g(x) = d[yA] . dy dy g(x) = 4y3. dy dx dac dx We have d

Solution for Question 2

r(t) = 3+ +2 +1 3t d [***] P = WW dt = (@P vodu u-dv at dt v2 Hence, (*) = (1+27) P 7€ - (72) (i+z+) It 자 2 z (H 27) r(A) (72

Solution for Question 3

f (x) - (5x+1)? sinta u f(x) = d [5x+1} (sinta] dx = (5x + 4(sin x ) + Sinºx 4( 5x+1)3 dre dac de dac = (5x+33.d (sinte).d (

Solution for Question 4

- cos (62) f(c) f(X) d coscevezy dae =d[ces ce)) dcery.d(x2) dez) dx d(x2) 2 e = - sinlezzy ex2 f(x) - 2 a qoe ede? sin(ex2)

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