Question

(1 point) Given R(t) = cos(36) i + e sin(3t) 3 + 3ek Find the derivative R) and norm of the derivative. R(t) = R (t) Then

(1 point)

Given

R(t)=e4tcos(3t)i+e4tsin(3t)j+3e4tkR(t)=e4tcos(3t)i+e4tsin(3t)j+3e4tk

Find the derivative R′(t)R′(t) and norm of the derivative.

R′(t)=R′(t)= ∥R′(t)∥=‖R′(t)‖=

Then find the unit tangent vector T(t)T(t) and the principal unit normal vector N(t)N(t)

T(t)=T(t)= N(t)=N(t)=

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Answer #1

mit Tangent vector :- THE Rit IRIt) <(4 eat ugat - Beltsin3t) (A e Alignotto Beatropi), 1242 Beat Тle) < 460 3+ -381n3, 4 si

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(1 point) Given R(t)=e4tcos(3t)i+e4tsin(3t)j+3e4tkR(t)=e4tcos(3t)i+e4tsin(3t)j+3e4tk Find the derivative R′(t)R′(t) and norm of the derivative. R′(t)=R′(t)= ∥R′(t)∥=‖R′(t)‖= Then...
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