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A weak acid, HF, is prepared with an initial concentration of 1.20 M. After reaching equilibrium, it has a pH of 1.551. What
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Answer #1

.               HF      \rightleftharpoons      H+      + OH-

Initial 1.2 M.             0              0

Change.    -x    +x         +x

Change.     (1.2-x)M    xM     x M

Given pH = 1.551

Since pH = - log [H+]

H+ = 0.0281 M

Percentage ionisation of the acid = (acid amount ionized/ initial acid )X100= (0.0281 M/1.2 M)X100= 2.34 Answer

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