Answer:
P6.a)Propagation delay dprop is equal to d/s where d is the distance and s is the wave propagation speed.
here m is the distance between 2 hosts.so dprop=m/s
b)Packet transmission time is obtained as,packet size/bit rate
here packet size is L and bit rate is R bps.
so dtrans=L/R
c)Ignoring processing and queuing delay an expression of end-to-end delay will be=m/s+L/R or dprop+dtrans
d)At time t=0 and t=dtrans then the last bit of a packet is leaving node A.
e)If dprop>dtrans then at t=dtrans first bit of packet leaves from node A at t=0 and it is in the link and not reached to node B yet.
f)If dprop<dtrans then at t=dtrans first bit of packet has reached to node B.
g)s=2.5x108 L=120bits R=56kbps then m=LR/s=120x56/2.5x105km/s=0.02688km/s.
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