Homework Answers
Given : pH = 5.33
We know that at 25 °C
Dissociation constant of water, Kw = 10-14
Hence pKw(which is -log(Kw)) = 14
Also, pH + pOH = 14
5.33 + pOH = 14
pOH = 8.67
-log[OH-] = pOH
[OH-] = 10^(-pOH)
[OH-] = 2.14 x 10-9 M
Therefore the correct option is II option = 2.1 x 10-9 M
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