Question

A rectangular loop of wire with sides H = 29 cm and W = 55 cm carries current l2 = 0.288 A. An infinite straight wire, located a distance L = 20 cm from segment ad of the loop as shown, carries current ly = 0.691 A in the positive y-direction. 1) What is Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop? N Submit 2) What is Fbcx, the x-component of the force exerted by the infinite wire on segment bc of the loop?. N Submit 3) What is Fnet, y, the y-component of the net force exerted by the infinite wire on the loop? N Submit

Answer 1

are equal along the Magnetic field at a anda path and The magnetic field due to I B- ll. I, 2TL L = 20cm = 0.2m. I = 0.691 F I (2B) where is ad e- 290m 2-029m F = IzX l xlo 7, 2TL 0-288 X 029 X 4.97 Xlo X 0.691 27 x 0.2 - 0.5771 x 107 h = 5.771x10N (6) Fe, BUI 21 (L+W) E = I2 IB -> T₂ = 0.288 Lew= 20cmt 55cm = e = 29cm = 0.29m 75cm - 0.75m

{= 1* ex UI, 21(Kw) { = 0.2888 0.29 Xanxlox0.691 27 X 0.75 = 0.15388107 E = 1.5389 x168N Feet = F,-F = 5.771x108 1.53867108 - 4.2 32x100 N cancels in eepward and downward Fare equally directions

- ZL TOBYE LIB Driection of current such that force (net) exerted on the loop will be toward left as net force due to Is is toward right. F-elexo) e is toward direction of current In branch be the force should be right so the magnetic field should be for that direction of Cearrent would be repword toward positive y direction) (net) due to I, = F,-F (Fret) due to Iz = Fz - for (F, E ore due to I, and F3 and fy are due to Iz ) Loop experience Gero force so - F = Fz ft I lB. - I l B = Iz l B - Il Bq e- ad-bc

B magnitude of magnetic field due to I, at a In cat b Iz at b Izcet a → B- BBB 27 7 dy II - U2 - No Izł 21L 20(LW) 251 (22) 215 (24+W) do f ( t - LEW) = 1653 ( 11 (24h) ) - Iz = 1, ( - LAW) Caziw) = 0.691 befoss) 0.2 0.2+0.55 2 +0.2 2*02+055 - 0.691 * 3.666 1.447 - 1.75066 Arary