Question

What is the value of t1 after execution of these statements if the value of t2 is as follows: chart1[6]; chart2 [ ]="Happy Studying": strncpy(t1, t2, 5); t1[5] = 'O'; Value of t1 is:

Answer 1

Answer 1: Happy

Solution explanation with code screenshot;-

Program code:-

#include <stdio.h>
#include <string.h>
int main()
{
//String of size 6 is defined
char t1[6];
char t2[]= "Happy Studying";
  
/*string t2 is being copied to string t1
only first 5 characters is copied to string t1.
*/
strncpy(t1,t2,5);
// delimiter '\0' assinged at t1[5] marking send of the srting
t1[5] = '\0';
  
printf("Value of t1 is: ");
for(int i=0; t1[i]!= '\0'; i++ )
printf("%c", t1[i]);
  
return 0 ;
}
Screenshot

main.c #include <stdio.h> 2 #include <string.h> 3 int main() 4-{ //String of size 6 is defined char t1[6]; char t2[]= "Happy Studying"; /*string t2 is being copied to string ti only first 5 characters is copied to string ti. strncpy(t1, t2,5); // delimiter 'lo' assinged at t1[5] marking send of the string t1[5] = '\0'; printf("Value of t1 is: "); for(int i=0; t1[i]!= '0'; i++) printf("%c", t1[i]); 18 19 20 21 return 0; } input Value of t1 is: Happy ... Program finished with exit code o Press ENTER to exit console.

Solution 2:- C if ( strcmp(a, b) == 0 ) somefun();

Explanation

somefun() will be called when the if clause will be true and this if clause will be true if variable a and b hold dame character.