1)
a)
(t-sqrt(3t+4))/(4-t)
So, at t=4, limit tends to 0/0
So, apply L'hospital rule
So,
it can be written as
-(1-3/sqrt(3t+4))
So, at t=4
Limit is -(1-3/4)=-1/4
b)
x*log(x)=log(x)/(1/x)
So, at x=0, limit is inf/inf
So,apply L'hospital rule
So,
(1/x)/(-1/x^2)=-x=0
So, LIMIT=0
2)
A)
Integral is 0 since the upper limit and lower limit of integral both are 0
b)
Apply lebnitz rule
So, g'(x)=exp(2x)*cos(1-5x)^2
c)
Apply lebnitz rule
So, it is
(-(x^8+1)/(x^4+1))*(2*x)
Calculus 1 MAT 201 Final Exam, Spring 1 2019, LAGCC Evaluate the following limits, you may...
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