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Question 3 In the figure, a block is accelerated from rest by a compressed spring and, after leaving the spring, encounters a
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Answer #1

Initial elastic potential energy stored in the spring,

U = (1/2)*k*d^2

= (1/2)*600*0.02^2

= 0.12 J

kinetic energy of the block when it leaves the spring, KE = 0.12 J

when the block moves on frictional surface it losses its total kinetic energy and the energy converted into thermal energy.

so, delta_Eth = 0.12 J <<<<<<<<--------------Answer

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