If the percent yield for the following reaction is 51.0%, how many grams of KClO3 are...
If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g)
If the percent yield for the following reaction is 65.0%, how many grams of KClO 3 are needed to produce 32.0 g of O 2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g) 126 g 283 g 53.1 g 81.7 g
4) if the percent yield for the following reaction is 65.0%, how many grams of KCIO3 are needed to produce 4.00 g of O2? 2 KCIO30)-2 KCHA) 3 020) A) 10.2g 8)6 63g C) 35 3g D) 157g
If 3.50 kJ was required for the following reaction, how many grams of KClO3 was produced? 2 KCl (s) + 3 O2 (g) → 2 KClO3 (s) ΔH = 84.9 kJ If there are 5.96 g of NO present, how much energy (kJ) will be produced? 2 NO (g) → 2 N2 (g) + O2 (g) ΔH = -180.0 kJ
When heated, kCLO3 decomposes into KCL and O2. 2KCLO3
→2 KCI + 302 If this reaction produced 51.3 g KCI, how many grams
of O2 were produced?
When heated, KCIO, decomposes into KCl and 0,- 2KCIO, — 2 KCI +30, If this reaction produced 51.3 g KCl, how many grams of O, were produced? mass: mass: [ 80,
Consider the following unbalanced reaction. Mg(s) + O2(g) → MgO(s) How many grams of O2 are needed to produce 142 g of MgO if the reaction has a 60.5% yield?
How many grams of potassium chlorate decompose to potassium chloride and 456 mL of O2 at 128°C and 777 torr? 2 KCIO3(s)2 KCI(s) +3 02 (g) g
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Question 2 1 pts Given the following unbalanced reaction: KCIO3 ---> KCI + O2 How many moles of Oz can be produced by letting 45.7 g of KCIO3 react? - Question 3 1 pts Given the following unbalanced reaction: Na2O + H2O ---> NaOH How many grams of NaOH is produced from 2.78 x 10 grams of Na O?
Question 4 1 pts Given the decomposition reaction of KClO3(s), 2 KCIO3(s) 2 KCl(s) + 3 O2(8) If 19.6 L of oxygen gas (O2) are produced at 198 °C and 760 torr, answer all three parts below. 1) The number of moles of O2(g) produced → [Select ] 1.21 mol 385 mol 2) The number of moles of KCIO3(s) require 0.507 mol 917 mol problem is Select] 2(g) as stated in the 2) The grams of KCIO3(s) required to produced...
C12H22O11(s) + 8 KClO3(s) -----> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3= 122.6 g/mol sucrose= 342.3 g/mol CO2= 44.01 g/mol 1 skittle= .84 grams of sucrose 1. If each skittle contains 0.84 g of sucrose (C12H22O11) What is the minimum number of skittles needed to maximize the product if I use 12.0g of KClO3? 2. How many grams of reactant remain (excess) after 2.5g of sucrose and 25.0g KClO3 react? 3. If 2.2 grams of CO2 are produced,...