If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are...

Question

Question

If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2?

2 KClO3(s) → 2 KCl(s) + 3 O2(g)

Answer 1

Answer #1

2 KCIO3(s) → 2 KCl (s) + 3O2(g) 2x122.55g KC10, should produce 3x32go, but 65.0% yiled ー×100-65 if 100% yield 3x 32 x 624g O2

Answer 2

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