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A positive charge 1.1X10-11 C is located 10-2 m away from a negative charge of the...

A positive charge 1.1X10-11 C is located 10-2 m away from a negative charge of the same magnitude. Point P is exactly half way between them --what is the E field at point P?

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Answer : Given that - 2 .: Q = 10 x 10 c 8=10 m I = 9x109 Nim? LITTE. The electric field at point p is 22 E = - (2x 109(2/1-1

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