A person pulls on a container on a horizontal frictionless surface with a force of 110 N in a direction of 40° above the horizontal. If the normal force on the container is 230 N, what is the mass of the container?
We can resolve the force applied by person into two components.
Fx = 110 cos 40 = 84.26 N
Fy = 110 sin 40 = 70.7 N
Therefore, total normal force is
N = 70.7 + 230 = 300.7 N
we know
N = mg
m = N / g
m = 300.7 / 9.8
m = 30.68 Kg
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