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If tcalc = -2.78, tcrit = 1.96, H0: Mu > Mu0, and Xbar < Mu0, what...

If tcalc = -2.78, tcrit = 1.96, H0: Mu > Mu0, and Xbar < Mu0, what will your conclusion be regarding the null hypothesis?

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Answer #1

Solution :

Given that,

tcalc = -2.78

tcrit = 1.96

tcalc > tcrit as |2.78| > 1.96

Reject the null hypothesis .

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