Question

8. A 1.50 kg rock is thrown straight up with an initial velocity of 14.9 m/s from a cliff. What is the impulse received from the force of gravity over the next 0.5 s? Assume positive direction up. (a) - 7.35 N.S (b) 29.35 Nos. (c) - 37.35 N:s (d) 37.35 N:s

Answer 1

Concept - find the final speed using equation of kinematics where initial velocity and time and acceleration are given. Impulse will be equal to the change in momentum of the rock. We use the velocity and mass to find the required impulse as shown below***************************************************************************************************
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V = Vi tat = 14.9 m/s + (-9.8m/s36055) = 10 m/s impulse = AP = m(uf-vi) = (1519) (10m/s – 14-9m/s) = -7.35 Nis