Given,
q = 6.32 pC ; a = 47.9 cm
The amount of work required will be equal to the potential energy of the given arrangement.
We know that
U = k q1q2/r12
for the given set up
distance between 2 +q and 2-q = sqrt(2) a
U = -k q^2/a + kq^2/sqrt(2)a + k q^2/sqrt(2)a - k q^2/a - kq^2/a - kq^2/a
U = k q^2/a (-1 + 1/sqrt(2) -1 - 1 + 1/sqrt(2) - 1)
U = k q^2/a x -2.586
U = 9 x 10^9 x (6.32 x 10^-12)^2/0.479 x -2.586 = -1.94 x 10^-12 J
Hence, U = -1.94 x 10^-12 J
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