Question

In the figure particle 1 of charge +q and particle 2 of charge +4q are held at separation L = 8.66 cm on an x axis. If particle 3 of charge 43 is to be located such that the three particles remain in place when released, what must be the (a) x and (b) y coordinates of particle 3 and (c) the ratio 93/q? (a) Number Units (b) Number Units (c) Number Units

Answer 1

- L Particle 1 having charge +9 & particle 2 having charge + 49. for equilibrium IF =0 for each particle. . Particle 3 must be in a position where forces Wil cancel out of 3rd partide any one side of 1 or 2 then forces will add & EF never be vere. . Particle 3 must be situated b/w 1 and 2. 1 Belt 2 x +49 force on particle 3 { F E + F z = 0 . Ez & misst equal magnitude bet Opposite direction. K. +9.93 kx +49. a. x2 L-22 ► hein -Ex - L-x=2x 30= L x = 1/3 Given L = 8.66cm af x= 8.66/3 = 2.89 cm by & y = 0 cm

force on 1 partide must be zero w 13 Z =0 If both 2 and 3 are arely charge then it will never zero. E = + = 0 " Magnitude of F mest be caual to F3 K. 1911921 - k 19:11931 LO 22 lat 31 49 > 95 4X?/- 4* (413) If on then force both 1 . 2 & 3 are the charge never be nero 3 mest be negative