Question

3.3 only

ted auvaRtageously for measuring distance: a) pacing: b) odometer, e) stadia; d) taping; e) EDM. 33 A surveyor counted the number of paces required to cover a 250-ft distance. The results were as follows: 95, 93, 97, 98, and 92 paces. Then an unknown distance was stepped off four times, requiring 115, 118, 116, and 117 paces. 3.13 Determine the average pace length and the length of the one of second line. 34 A surveyor paces a 400-ft length four times with the 1 following results: 140, 143, 141, and 142 paces. How many paces will be necessary for this surveyor to lay out a distance of 525 ft? Ans.: 2.632ft, 307 ft) angle 3.14 Detern 3.15 horizo 35 Convert the following distances given in meters to feet the ho using the latest meter definition that is based on the speed of light. a. 632.18 m b. 895.49 m c. 1254.30m 3.16 be 17 (Ans: 2074.08 ft) and th (Ans.: 2937.96ft) the ho (Ans.: 4115.16ft) vation 3.6 Convert the following angles to decimal values: a. 24°19'12" 3.17 and 90 b 50944 37N

Answer 1

95 93 97 98 92 Average Path Length = 250/95 + 250/93 + .... + 250/92/5 cong 2.632 ft Total Distance of second line = Average Path Length times Average Path cong 2.632 times (115 + 118 + 116 + 117)/4 cong 307 ft