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How would you draw the corresponding FBD and torque
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A magnesium tube (G-18GPa) of outer...
Problem 1: The Am1004-T61 magnesium tube is bonded to the A36 steel rod. If the allowable...
Problem 1: The Am1004-T61 magnesium tube is bonded to the A36 steel rod. If the allowable shear stress for the magnesium and steel are 45 MPa and 75 MPa respectively, determine the maximum torque that can be applied at A. Also determine the corresponding angle of twist. G-75GPa, Gmg=18GPa. shor sless mages
4. An Am1004-T61 magnesium tube is bonded to a central A36 steel rod. Sketch and label...
4. An Am1004-T61 magnesium tube is bonded to a central A36 steel rod. Sketch and label the shear stress distribution across the entire radius of the composite member when a torque of 4.8 kN-m is applied. Sketch the corresponding shear strain distribution. 900 mm 80 mimA 40 mm 80 mm4 40 mm 5. For the composite member of Problem 4, assume that both materials are perfectly plastic once they yield. Furthermore, assume that the shear yield stress of the magnesium...
4. An Am1004-T61 magnesium tube is bonded to a central A36 steel rod. Sketch and label...
4. An Am1004-T61 magnesium tube is bonded to a central A36 steel rod. Sketch and label the shear stress distribution across 900 mm the entire radius of the composite member when a torque of 4.8 kN m is applied. Sketch the corresponding shear strain distribution 80 mm 40 mm
A steel tube with a circular cross section has an outside diameter of 300 mm and...
A steel tube with a circular cross section has an outside diameter of 300 mm and wall thickness of 2 mm. The cylinder is twisted along its length of 2 m with a torque of 50 kN ยท m. (a) Determine the maximum torsional shear stress using Equation Theta= T*L/JG (b) Determine the maximum torsional shear stress using the closed thin-walled tube method. Compare this result to the result of part (a). (c) Assuming the tube does not yield, determine...
QUESTION 5 The copper pipe has an outer diameter of 40mm and an inner diameter of...
QUESTION 5 The copper pipe has an outer diameter of 40mm and an inner diameter of 37mm. If it is attached to the wall at point A and three torques are applied as shown, determine the minimum shear stress developed in the pipe. Answers should be given in units of MPa. 30 N m 20 N m 80 N m For the 30mm diameter shaft shown below made of steel (G-200GPa), what is the magnitude of the total angle of...
The hollow steel construction auger in Figure 4 has an outer diameter d2 = 140 mm...
The hollow steel construction auger in Figure 4 has an outer diameter d2 = 140 mm and thickness of t = 8 mm. The steel has a shear modulus of elasticity E = 200 GPa and v = 0.3. For an applied torque of 35 kN m, determine the following quantities: a) Shear stress at the mid-center of the thickness t of the shaft. [2] b) Shear stress on the outer surface. [1] c) Shear stress in the inner surface,...
Saved Question 20 1 points The following is the torque versus angle of twist diagram for...
Saved Question 20 1 points The following is the torque versus angle of twist diagram for a 0.75 inch diameter steel bar tested in torsion. The gage length of the bar is 3 inches. The angle of rotation and torque at points and Pare (0.8 radian, 1500 in-lb) and (11.3 radian, 4000 in-Ib) respectively. The power-law curve fitting relation for the data above the yield point is given by T-32980021, where T is in in-lb and is in radian Torque...
TORSION
a) A hollow circular shaft designed to have an inner diameter of 0.7Do; where Do is an outer diameter.i) Determine the inner and outer diameters of the shaft if the maximum allowable shearing stress is Y0 N/mm2 and torque is X00 kNm. Then, calculate the polar moment of inertia.ii) By using inner diameter calculated in (i), calculate the maximum shearing stress and a new torque, if the shaft is changed to solid circular shaft. The shaft is 1.5 m long with the twisted through...
Problem 1: The Am1004-T61 magnesium tube is bonded to the A36 steel rod. If the allowable shear stress for the magnesium and steel are 45 MPa and 75 MPa respectively, determine the maximum torque that can be applied at A. Also determine the corresponding angle of twist. G-75GPa, Gmg=18GPa. shor sless mages
4. An Am1004-T61 magnesium tube is bonded to a central A36 steel rod. Sketch and label the shear stress distribution across the entire radius of the composite member when a torque of 4.8 kN-m is applied. Sketch the corresponding shear strain distribution. 900 mm 80 mimA 40 mm 80 mm4 40 mm 5. For the composite member of Problem 4, assume that both materials are perfectly plastic once they yield. Furthermore, assume that the shear yield stress of the magnesium...
4. An Am1004-T61 magnesium tube is bonded to a central A36 steel rod. Sketch and label the shear stress distribution across 900 mm the entire radius of the composite member when a torque of 4.8 kN m is applied. Sketch the corresponding shear strain distribution 80 mm 40 mm
QUESTION 5 The copper pipe has an outer diameter of 40mm and an inner diameter of 37mm. If it is attached to the wall at point A and three torques are applied as shown, determine the minimum shear stress developed in the pipe. Answers should be given in units of MPa. 30 N m 20 N m 80 N m For the 30mm diameter shaft shown below made of steel (G-200GPa), what is the magnitude of the total angle of...
The hollow steel construction auger in Figure 4 has an outer diameter d2 = 140 mm and thickness of t = 8 mm. The steel has a shear modulus of elasticity E = 200 GPa and v = 0.3. For an applied torque of 35 kN m, determine the following quantities: a) Shear stress at the mid-center of the thickness t of the shaft. [2] b) Shear stress on the outer surface. [1] c) Shear stress in the inner surface,...
Saved Question 20 1 points The following is the torque versus angle of twist diagram for a 0.75 inch diameter steel bar tested in torsion. The gage length of the bar is 3 inches. The angle of rotation and torque at points and Pare (0.8 radian, 1500 in-lb) and (11.3 radian, 4000 in-Ib) respectively. The power-law curve fitting relation for the data above the yield point is given by T-32980021, where T is in in-lb and is in radian Torque...
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