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10. Suppose that the average weekly grocery bill for a family of four is $140 with a standard deviation of S10. If the next 52 weeks can be viewed as a random sample from a population with this center and spread, then the approximate probability that the total grocery bill for one year is less than $7020 is 0.0002. This problem can also be solved using the sampling distribution of the sample average. Complete probability statement.

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Solulon Given thot 드 140 7020-14 이 6 10 VS 1.3867 z 4961.4 prohabi ro bcability Stastement < 4961-4 Drahabisity

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